A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.620 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.

Answer 1

d1 = 0.5g*t^2 = 4.9*0.62^2 = 3.04 m = 1/2 the distance.

d = 0.5g*t^2 = 2*3.04 = 6.08 m.
4.9*t^2 = 6.08
t^2 = 1.24
t = 1.114 s. passed during entire trip.