h(t) = 41 -2t - t^2
h(t) = 0 when t = √42 - 1 = 5.48
. A boy is sitting in his red wagon at the top of a hill, holding onto a tree to keep from rolling down the hill. The distance from the top of the hill to the bottom is 41 meters. He pushes off from the tree at a starting velocity of 2 m/s, and then gravity accelerates the wagon at a constant rate of 2 m/s2. How long will it take him to reach the bottom of the hill (round to the nearest hundredth)?
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