Not enough information.
Work is defined as (the sum of) Force(s) dot displacement. So we'd need the direction of the displacement vector.
I guess you could argue that "carry" implies perfectly horizontal displacement. In which case, W = 0J.
In that case, the Force 100N [North] and the displacement is 500m [East / West]. Since the Force and displacement are perpendicular to each other, the dot product is 0, and the boy has done no work.
A boy carries 100N to 500m. How much work is done
2 answers
on the other hand if he carried it 500 m UP, then 100 * 500 = 50,000 Joules
The problem does not say direction so who knows?
The problem does not say direction so who knows?