a boxer throws a punch with a force of 1800 and that lasts 0.02 seconds what is the impulse of this punch?

Answer 1

Impulse is defined as the product of the force applied and the time duration over which the force is applied. It can be calculated using the formula:

\[ \text{Impulse} = \text{Force} \times \text{Time} \]

Given:

• Force = 1800 N (Newtons)
• Time = 0.02 s (seconds)

Now, we can substitute these values into the formula:

\[ \text{Impulse} = 1800 , \text{N} \times 0.02 , \text{s} = 36 , \text{Ns} \]

Therefore, the impulse of the punch is 36 Ns (Newton-seconds).