Question

a boxer throws a punch with a force of 1800 and that lasts 0.02 seconds what is the impulse of this punch?

Answer 1

Impulse is defined as the product of the force applied and the time duration over which the force is applied. It can be calculated using the formula:

\[
\text{Impulse} = \text{Force} \times \text{Time}
\]

Given:
- Force = 1800 N (Newtons)
- Time = 0.02 s (seconds)

Now, we can substitute these values into the formula:

\[
\text{Impulse} = 1800 \, \text{N} \times 0.02 \, \text{s} = 36 \, \text{Ns}
\]

Therefore, the impulse of the punch is **36 Ns (Newton-seconds)**.