A boxer throws a punch with a force of 1,500 N that lasts 0.03s. What is the impulse of this punch?(1 point)

Question

Responses

280 kg.m/s
280 kg.m/s

5,000 kg.m/s
5,000 kg.m/s

28 kg.m/s
28 kg.m/s

45 kg.m/s

Answer 1

Impulse is calculated using the formula:

\[ \text{Impulse} = \text{Force} \times \text{Time} \]

In this case, the force \( F \) is 1,500 N and the time \( t \) is 0.03 s. So we can calculate the impulse:

\[ \text{Impulse} = 1,500 , \text{N} \times 0.03 , \text{s} = 45 , \text{N.s} , (\text{or kg.m/s}) \]

Therefore, the answer is:

45 kg.m/s