conservation of momentum
3.21E4(-5.16)+5.18E4(2.38)=(summasses) V
solve for V
A boxcar of mass 3.21 x 10^4 kg is rolling south at 5.16 m/s when it collides and couples with another boxcar of mass 5.18 x 10^4 kg that is rolling north at 2.38 m/s. What is the velocity of the coupled boxcars after collision? Take north as positive and express your result to three significant digits.
Please help!
2 answers
-.505