After sketching a "position diagram", that is, a diagram showing the actual situation,
I made a vector diagram with a vertical side labelled 415 N, the side opposite the angle of 41°
as T1, and the side opposite the 34° angle as T2. The 3rd angle would be 105°
by the sine law:
T1/sin41 = 415/sin105
T1 = 415sin41/sin105 = ...
find T2 in the same way
A box weighing 415 N is hanging from two chains attached to an overhead bean at angles of 56 degrees and 49 degree. Find the magnitude of the tension in each chain algebraically.
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