A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of the incline, in degrees?

Answer 1

0=mgsinα - F(fr)=
=mgsinα - μN=
=mgsinα - μmgcosα.
μ=sinα/cosα =tanα
α =tan⁻¹0.58 =30.11º

Answer 2

15