A box of mass 5 kg is pulled along a horizontal frictionless surface by a force of 40N inclined @ 30dgrees. Calculate A)the work done by the force over a distance. B)the speed gained by the box after travelling 10m.

Answer 1

The force component in the direction of motion is 40 cos30 N = 34.64 N

A) 34.64 N * distance
(You left out the distance)

B) Set the work done over 10 m equal to final kinetic energy and solve for V.