Asked by Jen
A box is sliding down an incline tilted at an angle of 2.14° above horizontal. The box is sliding down the incline at a speed of 5.15 m/s. The coefficient of kinetic friction between the box and the incline is
0.387. How far does the box slide down the incline before coming to rest?
0.387. How far does the box slide down the incline before coming to rest?
Answers
Answered by
bobpursley
friction force: mg*.387*Cos2.14
PE gained(due to change height)=mg*sin2.14*distance
Initial KE+PE gained=frictionwork
1/2 m 5.15^2+mg*sin2.14*distance=mg*.387*Cos2.14*distance
solve for distance
PE gained(due to change height)=mg*sin2.14*distance
Initial KE+PE gained=frictionwork
1/2 m 5.15^2+mg*sin2.14*distance=mg*.387*Cos2.14*distance
solve for distance
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