friction force: mg*.387*Cos2.14
PE gained(due to change height)=mg*sin2.14*distance
Initial KE+PE gained=frictionwork
1/2 m 5.15^2+mg*sin2.14*distance=mg*.387*Cos2.14*distance
solve for distance
A box is sliding down an incline tilted at an angle of 2.14° above horizontal. The box is sliding down the incline at a speed of 5.15 m/s. The coefficient of kinetic friction between the box and the incline is
0.387. How far does the box slide down the incline before coming to rest?
1 answer
1 answer