A box is being pushed to the left parallel to the x-axis by a force of 23.0 N. A rope provides a second force of 33.8 N on the box, directed to the right at an angle of 39.0 deg. from the x-axis. What is the magnitude of the net force acting on the box ?
3 answers
-F1+F2•cos α=-23 +33.8•cos39°= 3.27 N
That is not the answer. That's what I thought it was but its not.
F(x)= -F1+F2•cos α=
=-23 +33.8•cos39°= 3.27 N
F(y) = F2•sin α =33.8•sin39°= 21.27 N
F(net) =sqrt{F(x)²+F(y)²}= sqrt{3.27²+21.27²}=21.52 N
=-23 +33.8•cos39°= 3.27 N
F(y) = F2•sin α =33.8•sin39°= 21.27 N
F(net) =sqrt{F(x)²+F(y)²}= sqrt{3.27²+21.27²}=21.52 N