Let the froce be F.
The horizontal component is Fx = F cos 30
That must equal the weight times 0.3.
F cos30 = 50 g * (0.3)
Solve for F.
A box having a mass of 50kg is dragged across a horizontal floor by means of a rope tied on the front of it. The coefficient of friction between the box and the floor is .3. If the angle between the rope and the floor is 30 degrees, what force must be excerted on the rope to move the box at uniform speed?
2 answers
75
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