The correct answer is: Start Fraction 3 over 12 End Fraction times Start Fraction 2 over 11 End Fraction.
To find the probability of drawing two Ns if the first letter is replaced before drawing the second, we follow these steps:
1. Determine the total number of letters in the box, which is 12 in this case.
2. Determine the number of Ns in the box, which is 3 in this case.
3. Calculate the probability of drawing the first N, which is: Start Fraction 3 over 12 End Fraction.
4. Since the first letter is replaced before drawing the second, the total number of letters in the box remains the same at 12.
5. However, since the first N was already drawn and replaced, there are now only 2 Ns left in the box.
6. Calculate the probability of drawing the second N, given that the first N was already drawn and replaced, which is: Start Fraction 2 over 11 End Fraction.
7. Multiply the probabilities of the two events (drawing the first N and drawing the second N) together to find the overall probability, which is: Start Fraction 3 over 12 End Fraction times Start Fraction 2 over 11 End Fraction.
A box has these letters inside it: B N T P N N T P B B N T. Which answer shows how to find the probability of drawing two Ns if the first letter is replaced before drawing the second?(1 point)
Responses
312.211
Start Fraction 3 over 12 End Fraction times Start Fraction 2 over 11 End Fraction
412.412
Start Fraction 4 over 12 End Fraction times Start Fraction 4 over 12 End Fraction
412+412
Start Fraction 4 over 12 End Fraction plus Start Fraction 4 over 12 End Fraction
48. 48
Start Fraction 4 over 8 End Fraction times Start Fraction 4 over 8 End Fraction
1 answer