A box has a volume given by the trinomial 2x^3-16x^2-40x. What are the possible dimensions of the box? Use factoring.

Answer 1

To find the possible dimensions of the box, we need to factor the given trinomial:

2x^3 - 16x^2 - 40x = 2x(x^2 - 8x - 20) = 2x(x - 10)(x + 2)

So the possible dimensions of the box are:

- Length = x - 10
- Width = x + 2
- Height = 2x

Note that x must be positive for the dimensions to make sense in the context of a box.