A box contains twelve candies, five reds, four greens, and three blues. You select one piece at random, then replace it, then you select another. If

Question

P(BG) is the probability of selecting a blue first and a green second, find the following probabilities.

a. P(RG)=



b. P(BB)=



c. P(GB)=



d. P(not RR)=

Answer 1

The important difference between this question and your previous one is that you are replacing the candy after you picked it.
you have 5 R's , 4 G's, and 3 B's for a total of 12
so Prob(BG) = (3/12)(4/12) = (1/4)(1/3) = 1/12

How does this calculation differ from our calculation in your previous post?
Do the rest in the same way.