There are a total of 7 balls, so the probability of picking a red ball on the first draw is 3/7. Since we don't replace the first ball before picking the second one, there are 2 red balls left and a total of 6 balls left. Therefore, the probability of picking a red ball on the second draw given that we picked a red ball on the first draw is 2/6 or 1/3.
To find the probability that both balls are red, we need to multiply the probability of picking a red ball on the first draw by the probability of picking a red ball on the second draw given that we picked a red ball on the first draw:
(3/7) * (1/3) = 1/7
Therefore, the probability that both balls are red is 1/7.
A box contains 3 red and 4 blue bálls.
If 2 balls are selected at random without replacement, one by one, find probability that both are red.
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1 answer