A box contains 19 yellow, 29 green and 37 red jelly beans.
If 14 jelly beans are selected at random, what is the probability that 5 are yellow?
3 answers
I got 19C5 * 66C5 / 85C14 = 0.0000273503, but my online hw is saying this answer's incorrect. Am I missing something?
Prob(yellow) = 19/85
prob(not yellow) = 66/85
Prob(your event)
= C(14,5) (19/85)^5 (66/85)^9
= .1146..
prob(not yellow) = 66/85
Prob(your event)
= C(14,5) (19/85)^5 (66/85)^9
= .1146..
Yeah, I just realized my mistake, it was 66C9 for the remainder of the selections, not 66C5. Thank you though
1 answer