A box contains 12 bulbs with 3 defective ones. If two bulbs are drawn from the box together.what is the probability that a)both bulbs are defetive b)both are non defective c)one bulb is defective?

Answer 1

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

c) 3/12 * 9/(12-1) = ?

Use the similar process for a and b.

Answer 2

3/20

Answer 3

what will be the answer