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A box contains 10 pink rubber bands and 20 brown rubber bands. What is the probability of picking a pink rubber band, putting it back, and then picking another pink rubber band? P(pink and then pink)
2 answers
I apologize for any inconvenience. The probability of picking a pink rubber band and then picking another pink rubber band, with replacement, can be calculated by multiplying the individual probabilities.
The probability of picking a pink rubber band on the first draw is 10/30, or 1/3. After replacing the rubber band, the probability of picking another pink rubber band on the second draw is also 1/3.
Therefore, the probability of picking a pink rubber band and then picking another pink rubber band is:
P(pink and then pink) = P(pink) x P(pink | pink)
= (1/3) x (1/3)
= 1/9
So the probability of picking a pink rubber band, putting it back, and then picking another pink rubber band is 1/9.
The probability of picking a pink rubber band on the first draw is 10/30, or 1/3. After replacing the rubber band, the probability of picking another pink rubber band on the second draw is also 1/3.
Therefore, the probability of picking a pink rubber band and then picking another pink rubber band is:
P(pink and then pink) = P(pink) x P(pink | pink)
= (1/3) x (1/3)
= 1/9
So the probability of picking a pink rubber band, putting it back, and then picking another pink rubber band is 1/9.