Asked by sandy
A box containing food supplies for a refugee camp was dropped from a helicopter flying horizontally at a constant elevation of 414.1 m. If the box hit the ground at a distance of 95.3 m horizontally from the point of its release, ...
a) what was the speed of the helicopter?
b) with what speed did the box hit the ground?
a) what was the speed of the helicopter?
b) with what speed did the box hit the ground?
Answers
Answered by
Henry
a. h = 0.5g*Tf^2.
h = 414.1 m.
g = 9.8 m/s^2.
Tf = ? = Fall Time.
Dx = Xo*Tf.
Dx = 95.3 m.
Xo = ? = Initial hor. speed.
b. Y = Yo + g*Tf.
Yo = 0.
Y = ? = Ver. component of total velocity.
Speed = Sqrt(Xo^2 + Y^2).
h = 414.1 m.
g = 9.8 m/s^2.
Tf = ? = Fall Time.
Dx = Xo*Tf.
Dx = 95.3 m.
Xo = ? = Initial hor. speed.
b. Y = Yo + g*Tf.
Yo = 0.
Y = ? = Ver. component of total velocity.
Speed = Sqrt(Xo^2 + Y^2).
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