173.28 J
KE = 1/2 * m * v^2
KE = 1/2 * 6 kg * (7.6 m/s)^2
KE = 1/2 * 6 kg * 57.76 m^2/s^2
KE = 173.28 J
Therefore, the kinetic energy of the bowling ball when it hits the pin is 173.28 J.
A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KE=12mv2
(1 point)
Responses
22.8 J
22.8 J
173.28 J
173.28 J
346.65 J
346.65 J
693.12 J
1 answer