B. (0.1,1.5)
To find the position of the ball after 7 seconds, we first need to find the horizontal and vertical components of the velocity.
The horizontal component of the velocity is given by:
Vx = V * cos(87°) = 1.5 m/sec * cos(87°) ≈ 0.1 m/sec
The vertical component of the velocity is given by:
Vy = V * sin(87°) = 1.5 m/sec * sin(87°) ≈ 1.5 m/sec
After 7 seconds, the horizontal distance traveled is given by:
x = Vx * t = 0.1 m/sec * 7 sec = 0.7 meters
After 7 seconds, the vertical distance traveled is given by:
y = Vy * t - 0.5 * g * t^2 = 1.5 m/sec * 7 sec - 0.5 * 9.8 m/s^2 * (7 sec)^2 ≈ 1.5 m
Therefore, the position of the ball after 7 seconds is approximately (0.7, 1.5), which is closest to option B. (0.1, 1.5).
A bowling ball is rolled down the alley with a constant velocity of 1.5 m/sec. at an angle of 87° to the starting line. The position of the person throwing the bowling ball can be represented by the point (0,0). Where is the ball after 7 seconds?
A. (0.5,10.5)
B. (0.1,1.5)
C. (10.5,10.5)
D. (29,200)
1 answer
3 answers