A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 16 over 24 , and the probability of randomly pulling out a strawberry candy is fraction 1 over 8 , what is the probability of randomly pulling out a pineapple candy?

(5 points)

Group of answer choices

fraction 5 over 8

fraction 3 over 8

fraction 4 over 8

fraction 6 over 8

5 answers

The sum of the probabilities of pulling out an orange, strawberry, and pineapple candy should equal 1.

Let x represent the probability of pulling out a pineapple candy.

Therefore, the equation would be:

16/24 + 1/8 + x = 1

Simplify the fractions:

2/3 + 1/8 + x = 1

8/12 + 3/24 + x = 12/12

8/12 + 1/8 + x = 12/12

8/12 + 3/24 + x = 12/12

3/3 - 1/3 + x = 1

2/3 + x = 1

x = 1 - 2/3

x = 1/3

Therefore, the probability of randomly pulling out a pineapple candy is fraction 1 over 3.
thats wrong
I apologize for the error in my calculation. Let's correct it.

We know that the total probability of pulling out each type of candy should equal 1:

Probability of orange candy + Probability of strawberry candy + Probability of pineapple candy = 1

Given information:

Probability of orange candy = 16/24 = 2/3
Probability of strawberry candy = 1/8

Let the probability of pulling out a pineapple candy be x.

2/3 + 1/8 + x = 1

Simplify the fractions:

16/24 + 3/24 + x = 24/24

19/24 + x = 24/24

x = 24/24 - 19/24

x = 5/24

Therefore, the correct answer is:

Probability of randomly pulling out a pineapple candy = 5/24
that is also wrong
I apologize for the mistake. Let's correct it:

Given:
Probability of pulling out an orange candy = 16/24 = 2/3
Probability of pulling out a strawberry candy = 1/8

Let x be the probability of pulling out a pineapple candy.

From the total probability rule:
2/3 + 1/8 + x = 1
(16/24) + (3/24) + x = 1
19/24 + x = 1
x = 1 - 19/24
x = 24/24 - 19/24
x = 5/24

Therefore, the correct probability of randomly pulling out a pineapple candy is 5/24.