a bootlenose dolphin jumps out of the water. the path the dolphin travels can be modeled by h=-0.2d^2+2d, where h represents the height of the dolphin in feet and d represents the horizontal distance.

Question

a) assume that all energy is conserved. what is the initial velocity with which the dolphin leaves the water? round your answer to the nearest hundredth. (Disregard water resistance; g=32f/s^2

b) Convert the initial velocity to mph. Round your answer to the nearest hundredth. (1 mile= 5,280 feet)

Answer 1

h=-.2d^2+2d

dh/dt=-.4d dd/dt+2dd/dt

so at max height, dh/dt=0

0=(-.4d+2)dd/dt

but dd/dt is the horizontalveloicy, it can be anything. d=5ft

So without knowing horizontal velocity, I don't know how you can solve for initial velocity.