work done=2.0*1.5
friction=.4*1.5
in 1 secnod, it goes 1.5 m
KE=work done-friction=1.6*1.5 joules
power=KE/time=1.6*1.5/1 watts
a book,initially at rest is pushed along a horizontal table top by a horizontal force of 2N. After 1s it has been moved 1.5m. The force of friction is 0.4N
a.how much work is done on the book by the 2N force?
b.how much work is done on the book by friction?
c.what is the books kinetic energy after 1s?
d.what power is required?
1 answer
1 answer