g = 32.2 ft/s^2. Solve
Y = 14,400 = (1/2)g t^2
for t.
Multiply that "t" by the plane's speed to get the horizontal movement. Do it in feet:
600 mph = 880 ft/s
a bomb is dropped drom an airplane at an altitude of 14,400 feet how long would it take to reach the ground? (because the motion of the plane, the fall will not be vertical, but the time will be the same as that for a vertical fall.) the plane is moving at 600miles per hour. how far will th bomb move horizontally after it is released from the plane.
i got a formula but don't see how it works cause i don't have g. 1/2gt^2
horizontal distance vi*time
1 answer
1 answer