a = 16 cm/s^2
= .16 m/s^2
s = v0*t + 1/2 at^2, so
5t + .08t^2 = 200
t = 27.7
v = v0+at
= 5 + .16*27.7
= 9.4 m/s
) A body with an initial velocity of 5ms‾¹ accelerate uniformly at the rate of 16 cm s‾²
over a distance of 200 m. Calculate: (i) the acceleration in m s‾² (ii) its final velocity in m s‾¹
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