A body weighs low with a speed of 5N/s-1 in horizontal circle path of radius 5m. Calculate the magnitude of centripetal force acting on the body (g=10m/s-2

Answer 1

To find the magnitude of the centripetal force acting on the body, we can use the equation:

F_c = (m * v^2) / r

where F_c is the centripetal force, m is the mass of the body, v is the speed of the body, and r is the radius of the circle path.

In this case, the speed of the body is given as 5 N/s^-1, which is a unit of force rather than speed. We need to convert this to meters per second (m/s). Since the acceleration due to gravity is given as 10 m/s^2, we can set up the equation:

5 N/s^-1 = m * 10 m/s^2

Solving for m, the mass of the body:

m = (5 N/s^-1) / (10 m/s^2)

m = 0.5 kg

Now we can substitute the values into the centripetal force equation:

F_c = (0.5 kg * (5 N/s^-1)^2) / 5 m

F_c = (0.5 kg * 25 N^2/s^-2) / 5 m

F_c = 12.5 N

Therefore, the magnitude of the centripetal force acting on the body is 12.5 N.