A body weighs 0.30N in air, 0.25N when fully immersed in liquid. Calculates (a). It's loss in weight in water (b). It's relative density (c). Relative density of the liquid.

Answer 1

To calculate the loss in weight in water, we need to find the difference between the weight in air and the weight in water:

(a) Loss in weight in water = Weight in air - Weight in water
= 0.30N - 0.25N
= 0.05N

(b) To find the relative density of the body, we can use the formula:

Relative density = Weight in air / (Weight in air - Loss in weight in water)
= 0.30N / (0.30N - 0.05N)
= 0.30N / 0.25N
= 1.2

(c) To find the relative density of the liquid, we can use the formula:

Relative density of liquid = Weight in air / (Weight in air - Weight in liquid)
= 0.30N / (0.30N - 0.25N)
= 0.30N / 0.05N
= 6

Therefore, the loss in weight in water is 0.05N, the relative density of the body is 1.2, and the relative density of the liquid is 6.