A body vibrates in simple harmonic motion with the frequency of 50hz and amplitude of 4cm, find period, acceleration at the middle and the end of the path of oscillation.
2 answers
I need the solution
period is 1/f = 0.02
y = 0.04 sin (2 pi f t) = 0.04 sin (100 pi t)
v = 0.04 (100 pi) cos (100 pi t)
a = -0.04 (100 pi)^2 sin (100 pi t) = - (100 pi)^2 y so acceleration at middle is zero:) and at max is 0.04 (100 pi)^2
y = 0.04 sin (2 pi f t) = 0.04 sin (100 pi t)
v = 0.04 (100 pi) cos (100 pi t)
a = -0.04 (100 pi)^2 sin (100 pi t) = - (100 pi)^2 y so acceleration at middle is zero:) and at max is 0.04 (100 pi)^2
4 answers