Using the kinematic equation for uniformly accelerated motion:
s = ut + (1/2)at^2
where:
s = distance
u = initial velocity (0 m/s)
a = acceleration (5 m/s^2)
t = time
Converting the distance from kilometers to meters:
1 kilometer = 1000 meters
s = 1000 meters
Plugging in the values into the equation:
1000 = 0*t + (1/2)(5)(t^2)
1000 = (1/2)(5)(t^2)
1000 = 2.5t^2
Dividing both sides of the equation by 2.5:
400 = t^2
Taking the square root of both sides:
t = √400
t = 20 seconds
Therefore, it would take the body 20 seconds to cover a distance of 1 kilometer.
A body starts from rest and accelerates uniformly at 5m/s-2.calculate the time taken by the body to cover a distance of 1 kilometre
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