a body rolled on a surface with speed of 10m/s comes to rest after covering distance of 50 m find cofficient of friction

Answer 1

v^2 - u^2 = 2as

0-100=2*a*50

-100/100=a

a=-1 m/s^2
Negative sign shows reduction.

let n be the coeff. of friction,

n*mg=m*a
n=a/g
n=1/9.8

n=0.102

Answer 2

Good