F = ma
v = at
KE = 1/2 mv^2
A body of mass 4kg is acted on by a constant force of 12N for 3 seconds. Determine the kinetic energy gained by the body at the end of the time.
2 answers
F=ma
V= at
K.E= 1/2mv^2
==K.E = 1/2m(at)^2
=1/2ma^2t^2
=1/2ma *a*t^2
=1/2F*a*t^2
a=g
V= at
K.E= 1/2mv^2
==K.E = 1/2m(at)^2
=1/2ma^2t^2
=1/2ma *a*t^2
=1/2F*a*t^2
a=g
2 answers