conserve momentum.
4.0*2.5 + 0.2*0 = (4.0+0.2)*v
A body of mass 4.0 kg moving with a speed of 2.5 m/s collides with a stationary body of mass 0.2 kg. if the two bodies stick together after collision, calculate the magnitude of the velocity with which they move.?
3 answers
Given: M1 = 4kg, V1 = 2.5m/s.
M2 = 0.2kg, V2 = 0.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1+M2*V2 = M 1*V3+M2*V3
4*2.5+0.2*0 = 4V3+0.2V3
4.2V3 = 10
V3 = 2.4 m/s.
M2 = 0.2kg, V2 = 0.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1+M2*V2 = M 1*V3+M2*V3
4*2.5+0.2*0 = 4V3+0.2V3
4.2V3 = 10
V3 = 2.4 m/s.
A body of mass 4.0kg move with a velocity of 6m/s calculate the momentum of the body