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A body of mass 300g is whirled in a horizontal circle by means of a 60cm long cord. If the cord can sustain a tension of 400N before, find the max. number of revolution per minute which the body can have

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m omega^2 R = 400

0.300 w^2 (0.60) = 400
solve for w ( omega ) in radians/sec

then
w * 1 rev/2pi rad * 60 sec/min

= RPM

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