energy (kinetic) is ... 1/2 * 2 * 3^2
work done by friction equals initial energy
frictional force * distance = K.E.
frictional force = weight * coefficient
m g * μ * 2.5 = K.E.
solve for μ
A body of mass 2kg, moving at 3ms-¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction (g=10ms-²).
Please I need the full solution.
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