A body of mass 25kg moving at 3m/s on rough horizontal floor is brought to rest after shifting through a distance of 2.5m on the floor. calculate the coefficient of sliding friction

Answer 1

F = - mu m g = m a
so what is a?
average speed = (3+0)/2 = 1.5 m/s
so t = 2.5 meters / 1.5 m/s = 1.67 seconds
v = Vi + a t
0 = 3 + 1.67 a
a = -1.8 m/s^2
back to
-mu m g = m a
mu = a/g = 1.8/g = 0.183