A body of mass 10kg is moving with velocity 10m/sec.The work done to stop the body is :

Question

A) 500J B)-500J C)1000J D)-1000J

How to calculate the answer?

Answer 1

The kinetic energy of a body of mass m=10kg moving at v=10m/s is
E=(1/2)mv²
After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left.
So we can find
Work done=loss/reduction in kinetic energy.

Answer 2

1000j

Answer 3

500j

Answer 4

m=10kg,v=10m/s, ke=1/2×10×10×10=500

Answer 5

500j