A body Of mass 0.6 kg is thrown vertically upward from the ground with a speed of 20m\s calculate it's potential energy at the maximum height reached

Answer 1

To calculate the potential energy at the maximum height reached, we need to find the gravitational potential energy of the body.

The gravitational potential energy (PE) is given by the equation:
PE = m * g * h

Where:
m = mass of the body (0.6 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2, usually rounded to 10 m/s^2 for simplicity)
h = height

At the maximum height reached, the velocity of the body is 0 m/s. Therefore, all the initial kinetic energy is converted into potential energy.

The initial kinetic energy (KE) is given by the equation:
KE = (1/2) * m * v^2

Where:
m = mass of the body (0.6 kg)
v = velocity of the body (20 m/s)

Substituting the values into the equation:
KE = (1/2) * 0.6 kg * (20 m/s)^2
KE = 120 J

Since KE is converted into potential energy at the maximum height reached, the potential energy is equal to the initial kinetic energy:
PE = 120 J

Therefore, the potential energy at the maximum height reached is 120 J.