A body of mass 0.05kg falls from the height of 3m into a pile of send .the body penetrates the sand to a distant of 0.03m before stopping .what force is exerted by the sand

Answer 1

force*distance=.05*9.8*3
solve for force

Answer 2

-7.5n

Answer 3

Data:- m=0.05kg
U=0 m/s
G=9.8m/s
S=3m

Formula:- """ V²=u²+2gs""""
V²=(0)²+2(9.8)×3
V²=0+19.6×3
V²=58.8
V=√58.8
="""""V=7.66m/s""""

Data:-
V=7.66m/s
S=0.03m
V=0
a=?
Formula:-. """" V²=u²+2as""""
i.e. a=v²-u²/2s
a=(7.66)²-(0)²/2(0.03)
a=58.67-0/0.06
a=58.67/0.06
""""a=977.83m/s²""

Force=?

We know that,
F= ma
F=0.05×977.83
""""""F=48.8915N"""""

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