A body moving with uniform acceleration has a velocity of 12cm /a when its x coordinate is 3cm. If its x coordinates 2s later is -5cm, what is the magnitude of its acceleration

Answer 1

a=change velocity/time=(vf-vi)/2

vi=12
consider position:
sf=si+at
-5=3+a*2 or a=-4cm/s^2

Answer 2

Answer the question