A body moving with an initial velocity of 10m/s has a uniform acceleration of 2m/s.Find distance travelled in the 8th second of its motion?

Answer 1

s(t) = 10t + t^2
s(7) = 70+49 = 119
s(8) = 80 + 64 = 144

distance in 8th second = 144-119 = 25m

or, s = ∫[7,8] 10+2t dt

Answer 2

26m/s