a body is thrown vertically upward fron a certain height of pole and their velocity is 100m/s and then it returns to the ground in 6second then find the height of the pole ?

Answer 1

y = h + 100t - 4.9t^2
and you know that y=0 at t=6, so

h + 100*6 - 4.9*36 = 0

I suspect a typo...