a body is projected horizontally with a velocity of 80m/s from the top of a tower 160m above the ground. find the time of flight,range,velocity at which the body strikes the ground

Answer 1

Vertical problem is falls 160 meters with no initial vertical speed, time same as a rock falling
so
a = -9.81 m/s^2
v = 0 - 9.81 t
0 = 160 + 0 t - (1/2)(9.81)t^2
so
t = sqrt (320/4.9) = 8.08 seconds falling
Now horizontal
no horizontal force so no change in horizontal speed
u = 80 m/s
d = 80 m/s * 8.08 s
about 646 meters on earth

Answer 2

the final velocity is the square root
... of the sum of the squares of the horizontal and vertical components

horizontal = 80 m/s

vertical = g * flight time ... or √(2 * g * 160)

Answer 3

I dont no.

Answer 4

physics