A body accelerates uniformly from rest of 2m/s2.calculate its velocity after travelling 9 metres

Answer 1

To find the velocity of the body after traveling 9 meters, we can use the following equation of motion:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity (0 m/s as it starts from rest)
a = acceleration (2 m/s^2)
s = displacement (9 meters)

Plugging in the values, we get:

v^2 = 0^2 + 2(2)(9)
v^2 = 0 + 36
v^2 = 36

Taking the square root of both sides to find v:

v = √36
v = 6 m/s

Therefore, the velocity of the body after traveling 9 meters is 6 m/s.