A boat start sailing on Monday 10:00 at harbour A and sails 600km due north. Later it turns east for a further 420km to reach harbour B on Tuesday at 12:00.a)find total displacement from A-B average. b)speed of the trip.c)average velocity

Answer 1

a. displacement = sqrt(600^2+420^2)

b. distance = 600+420 = 1020
so speed = 1020/time

c.average velocity = answer from part a / time
but velocity also has a direction since it is a vector
tan angle east of north = 420/600

Answer 2

thanks that was very helpful 🙏