A boat moving at 5 mi/h is to cross a river in which the current is flowing at 3 mi/h. In what direction should the boat head to reach a point on the other bank of the river directly opposite the starting point?

Answer 1

X = Vc = 3 m/s.
Y = Vb = 5 m/s.

Tan A = Y/X = 5/3 = 1.66667.
A = 59o N. of E. = 31o E. of N.

Direction = 31o W. of N.