A boat moving at 15 km/h relative to water is crossing a river 1.5 km wide. The river flows at 5.0 km/h

Question

a) if the boat heads directly for the opposite shore, how long will the trip take?
b)Where will the boat arrive on the opposite shore?
c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?
d)How long will the crossing take in case c)?

Answer 1

It will take 1.5/15 hr to get across

IT does downstream 5*1.5/15 km

For the c), draw the triangle. On side is 5km/hr, the hypotenuse is 15km/hr. Solve for the side going straight across, that is the velocity across. For the angle, SinTheta=5/15

Answer 2

i didn't get the answer of bob very well. can he help me more widely.
the question is

Q)A boat moving at 15 km/h relative to water is crossing a river 1.5 km wide. The river flows at 5.0 km/h
a) if the boat heads directly for the opposite shore, how long will the trip take?
b)Where will the boat arrive on the opposite shore?
c)If the boat is to reach a point directly across from the starting point , in which direction should the boat head?
d)How long will the crossing take in case c)?

Answer 3

use this, Vx = dx * t
then use that t and find
Vy = dy * t
x and y are x dimension n y dimension
uhh..
i'll just do it,
Vx= 15 km/hr
dx = 1.5 km
dy = 5 km/hr