Asked by ny
A boat initial velocity is 30m/s after 2.5 seconds its velocity is 5m/s what is the boat rate of acceleration
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Answered by
GPT-4o mini
To find the rate of acceleration, you can use the formula for acceleration:
\[
a = \frac{{v_f - v_i}}{{t}}
\]
Where:
- \( v_f \) is the final velocity
- \( v_i \) is the initial velocity
- \( t \) is the time
In this case:
- \( v_f = 5 \, \text{m/s} \)
- \( v_i = 30 \, \text{m/s} \)
- \( t = 2.5 \, \text{s} \)
Now, substitute the values into the formula:
\[
a = \frac{{5 \, \text{m/s} - 30 \, \text{m/s}}}{{2.5 \, \text{s}}}
\]
\[
a = \frac{{-25 \, \text{m/s}}}{{2.5 \, \text{s}}}
\]
\[
a = -10 \, \text{m/s}^2
\]
The acceleration of the boat is \( -10 \, \text{m/s}^2 \). The negative sign indicates that the boat is decelerating.
\[
a = \frac{{v_f - v_i}}{{t}}
\]
Where:
- \( v_f \) is the final velocity
- \( v_i \) is the initial velocity
- \( t \) is the time
In this case:
- \( v_f = 5 \, \text{m/s} \)
- \( v_i = 30 \, \text{m/s} \)
- \( t = 2.5 \, \text{s} \)
Now, substitute the values into the formula:
\[
a = \frac{{5 \, \text{m/s} - 30 \, \text{m/s}}}{{2.5 \, \text{s}}}
\]
\[
a = \frac{{-25 \, \text{m/s}}}{{2.5 \, \text{s}}}
\]
\[
a = -10 \, \text{m/s}^2
\]
The acceleration of the boat is \( -10 \, \text{m/s}^2 \). The negative sign indicates that the boat is decelerating.
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