same type of question as your previous one.
Let's see you do some of the work, show me what you did.
A boat heads 15 degrees west of north with a water speed of 3 m/s. Determine its velocity relative to the ground when there is a 2 m/s current from 40 degrees east of north.
4 answers
Kim = Luke!!
How silly to switch names. Pick one and keep it!
How silly to switch names. Pick one and keep it!
I drew and labeled a triangle with one side to be found (v). I used the ‘z’ pattern to find 55 degrees. Then:
V^2= (2)^2+(3)^2-2(3)(2)cos 55
= 2.5 m/s
^this is correct, I just don’t really know how to find the angle (the text book answer is N56W but I got N41W using sine law
V^2= (2)^2+(3)^2-2(3)(2)cos 55
= 2.5 m/s
^this is correct, I just don’t really know how to find the angle (the text book answer is N56W but I got N41W using sine law
you were so close.
41.483° is indeed the angle within the triangle.
However, if you add 15° to that answer you get the direction of the boat.
N (41.483+15)° W or appr N 56 W.
btw, the question was to find its velocity relative to the ground
"relative to the ground" ? What does that even mean?
41.483° is indeed the angle within the triangle.
However, if you add 15° to that answer you get the direction of the boat.
N (41.483+15)° W or appr N 56 W.
btw, the question was to find its velocity relative to the ground
"relative to the ground" ? What does that even mean?